Given an integer array nums, return true if any value appears at least twice in the array, and return false if every element is distinct.
Input: nums = [1,1,1,3,3,4,3,2,4,2]
Input: nums = [3,1,4,2]
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To solve this problem in linear time complexity (O(n)), you can use the following algorithm:
xin the array: a. If
true. b. Otherwise, add
Here is some example code in Python that implements this algorithm:
duplicates = set()
for x in nums:
if x in duplicates:
This algorithm has a time complexity of O(n), as it requires iterating through the array once and performing a constant number of operations for each element.
I hope this helps! Let me know if you have any questions.